Đáp án: 

• \( \overrightarrow{AB} = (-1, 2, 2)\)
• \(\overrightarrow{AC} = (1, 1, -1) \)

\(\Rightarrow [\overrightarrow{AB}, \overrightarrow{AC}] = (-4, 1, -3) \)

•  \( S_{\triangle ABC} = \frac{1}{2} \left| [\overrightarrow{AB}, \overrightarrow{AC}] \right| = \frac{1}{2} \sqrt{16 + 1 + 9} = \frac{\sqrt{26}}{2} \)

•  \( AB = \sqrt{1 + 4 + 4} = 3 \)

\( S_{\triangle ABC} = \frac{1}{2} .AB .d(C, AB) \)

\(\Rightarrow d(C, AB) = \frac{2S_{\triangle ABC}}{AB} = \frac{\sqrt{26}/2}{3} = \frac{\sqrt{26}}{3} \)

\(\Rightarrow\) Vậy chọn \(\boxed{\text{C}} \)