Lời giải:
\(= 6[x^2 + (m - 1)x + m - 2] = 0 \)
\(\Leftrightarrow \left[ \begin{array}{} x = -1 \\ x = 2 - m \end{array} \right.\)
\(\Leftrightarrow \left\{ \begin{array}{l} 2 - m \neq -1 \\ -3 < 2 - m < 3 \end{array} \right. \Leftrightarrow \left\{ \begin{array}{l} m \neq 3 \\ -1 < m < 5 \end{array} \right. \)